If the magnitude of sum of two vectors is equ | vedclass

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Question

$\begin{array}{l}
Let\,the\,two\,vectors\,be\,\vec A\,and\,\vec B\,.\
Then,\,magnitude\,of\,sum\,of\,\vec A\,and\,\vec B\,,\
\,\,\,\,\,\,\,\,\lef

Vedclass · Accepted Answer

$90$

Vedclass · Answer

$\begin{array}{l}
Let\,the\,two\,vectors\,be\,\vec A\,and\,\vec B\,.\
Then,\,magnitude\,of\,sum\,of\,\vec A\,and\,\vec B\,,\
\,\,\,\,\,\,\,\,\left| {\vec A + \vec B} ight| = \sqrt {{A^2} + {B^2} + 2AB\cos 	heta } \
and\,magnitude\,od\,difference\,of\,\vec A\,and\,\vec B\,,\
\,\,\,\,\,\,\,\left| {\vec A - \vec B} ight| = \sqrt {{A^2} + {B^2} - 2AB\cos 	heta } \,,\
\,\,\,\,\,\,\,\left| {\vec A + \vec B} ight|\, = \,\,\left| {\vec A - \vec B} ight|\,\,\left( {given} ight)
\end{array}$

$\begin{array}{l}
or\,\,\sqrt {{A^2} + {B^2} + 2AB\cos 	heta } \
\,\,\,\, = \sqrt {{A^2} + {B^2} - 2AB\cos 	heta } \
 \Rightarrow \,\,4\,AB\cos 	heta  = 0\
\,\,\,\,4\,AB 
e 0,\,\,	herefore \cos 	heta  = 0\,or\,	heta  = {90^ \circ }
\end{array}$

If the magnitude of sum of two vectors is equal to the magnitude of difference of the two vectors, the angle between these vectors is ........ $^o$

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